4^x=3+18(4^-x)

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Solution for 4^x=3+18(4^-x) equation: 



4^x=3+18(4^-x)

We move all terms to the left:

4^x-(3+18(4^-x))=0



We calculate terms in parentheses: -(3+18(4^-x)), so:

3+18(4^-x)

determiningTheFunctionDomain
18(4^-x)+3

We multiply parentheses

-18x+3+

We add all the numbers together, and all the variables

-18x

Back to the equation:

-(-18x)



We get rid of parentheses

4^x+18x=0

We add all the numbers together, and all the variables

18x+4^x=0

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